How many even numbers of 3 different digits c | vedclass

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(A) To form a $3$-digit even number,the last digit (units place) must be an even digit.Available digits are $\{1, 2, 3, 4, 5, 6, 7, 8, 9\}$.The even d

Vedclass · Accepted Answer

$224$

Vedclass · Answer

(A) To form a $3$-digit even number,the last digit (units place) must be an even digit.Available digits are $\{1, 2, 3, 4, 5, 6, 7, 8, 9\}$.The even digits available are $\{2, 4, 6, 8\}$.Step $1$: The units place can be filled in $4$ ways (choosing $2, 4, 6,$ or $8$).Step $2$: Since repetition is not allowed,we have $8$ remaining digits for the tens place.Step $3$: We have $7$ remaining digits for the hundreds place.Total number of even numbers = $4 	imes 8 	imes 7 = 224$.

How many even numbers of $3$ different digits can be formed from the digits $1, 2, 3, 4, 5, 6, 7, 8, 9$ (repetition is not allowed)?

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