(C) Glucose is a hexose sugar,which contains $6$ carbon atoms per molecule.In the Calvin cycle,each turn fixes $1$ molecule of $CO_2$.To produce $1$ m

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(C) Glucose is a hexose sugar,which contains $6$ carbon atoms per molecule.In the Calvin cycle,each turn fixes $1$ molecule of $CO_2$.To produce $1$ molecule of glucose $(C_6H_{12}O_6)$,$6$ turns of the Calvin cycle are required.Therefore,to produce $5$ molecules of glucose,the number of cycles required is $5 \times 6 = 30$ cycles.