(B) Given,$\sin \alpha = \frac{1}{2} = \sin 30^{\circ}$ $\left[\because \sin 30^{\circ} = \frac{1}{2}\right]$$\Rightarrow \alpha = 30^{\circ}$And,$\co

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(B) Given,$\sin \alpha = \frac{1}{2} = \sin 30^{\circ}$ $\left[\because \sin 30^{\circ} = \frac{1}{2}\right]$$\Rightarrow \alpha = 30^{\circ}$And,$\cos \beta = \frac{1}{2} = \cos 60^{\circ}$ $\left[\because \cos 60^{\circ} = \frac{1}{2}\right]$$\Rightarrow \beta = 60^{\circ}$Therefore,$\alpha + \beta = 30^{\circ} + 60^{\circ} = 90^{\circ}$

Class 10 Mathematics Introduction to Trigonometry Mix Examples - Introduction to Trigonometry

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Given that $\sin \alpha = \frac{1}{2}$ and $\cos \beta = \frac{1}{2}$,then the value of $(\alpha + \beta)$ is (in $^{\circ}$)

A
$0$
B
$90$
C
$30$
D
$60$

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Introduction to Trigonometry

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Mix Examples - Introduction to Trigonometry

$\tan (90^\circ - \theta) = \ldots \ldots \ldots$

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Write 'True' or 'False' and justify your answer.
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

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If $\sqrt{3} \tan \theta = 1$,then find the value of $\sin^{2} \theta - \cos^{2} \theta$.

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$\frac{\cos 50^{\circ}}{\sin 40^{\circ}} + \frac{\sin 15^{\circ}}{\cos 75^{\circ}} = \ldots \ldots \ldots \ldots$

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If $\sec \theta = \frac{5}{3}$,then $\tan \theta = \ldots$

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Given that $\sin \alpha = \frac{1}{2}$ and $\cos \beta = \frac{1}{2}$,then the value of $(\alpha + \beta)$ is (in $^{\circ}$)

Similar Questions

$\tan (90^\circ - \theta) = \ldots \ldots \ldots$

Write 'True' or 'False' and justify your answer.$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$

If $\sqrt{3} \tan \theta = 1$,then find the value of $\sin^{2} \theta - \cos^{2} \theta$.

$\frac{\cos 50^{\circ}}{\sin 40^{\circ}} + \frac{\sin 15^{\circ}}{\cos 75^{\circ}} = \ldots \ldots \ldots \ldots$

If $\sec \theta = \frac{5}{3}$,then $\tan \theta = \ldots$

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Write 'True' or 'False' and justify your answer.
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}=1$