tan (90^circ - theta) = ldots ldots ldots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ -

Vedclass · Accepted Answer

$\cot 	heta$

Vedclass · Answer

(B) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ - 	heta) = \sin 	heta$$	an (90^\circ - 	heta) = \cot 	heta$$\cot (90^\circ - 	heta) = 	an 	heta$$\sec (90^\circ - 	heta) = \operatorname{cosec} 	heta$$\operatorname{cosec} (90^\circ - 	heta) = \sec 	heta$Therefore,$	an (90^\circ - 	heta) = \cot 	heta$.

$\tan (90^\circ - \theta) = \ldots \ldots \ldots$

Similar Questions

If $0 < \theta < 90$ and $\sin \theta = \cos 30$,then $2 \tan^2 \theta - 1 = \dots$

$\cos 35^{\circ} = \ldots \ldots \ldots$

If $\cos A = \frac{4}{5}$,then the value of $\tan A$ is

$\cos (40^{\circ}-\theta)-\sin (50^{\circ}+\theta) = \ldots \ldots \ldots \ldots$

If $\sec \theta = \frac{13}{5}$,then $\cos \theta = \ldots \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module