Given that:2C_{(s)} + 2O_{2(g)} to 2CO_{2(g)} | vedclass

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(D) The target reaction for the formation of acetylene is: $2C_{(s)} + H_{2(g)} 	o C_2H_{2(g)}$.Let the given equations be:$(i) 2C_{(s)} + 2O_{2(g)}

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$+228$

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(D) The target reaction for the formation of acetylene is: $2C_{(s)} + H_{2(g)} 	o C_2H_{2(g)}$.Let the given equations be:$(i) 2C_{(s)} + 2O_{2(g)} 	o 2CO_{2(g)}; \Delta H_1 = -787 \ kJ$$(ii) H_{2(g)} + 0.5 O_{2(g)} 	o H_2O_{(l)}; \Delta H_2 = -286 \ kJ$$(iii) C_2H_{2(g)} + 2.5 O_{2(g)} 	o 2CO_{2(g)} + H_2O_{(l)}; \Delta H_3 = -1301 \ kJ$To obtain the target reaction,perform the operation: $(i) + (ii) - (iii)$.$\Delta H_f = (-787) + (-286) - (-1301)$$\Delta H_f = -1073 + 1301 = +228 \ kJ$.

Given that:
$2C_{(s)} + 2O_{2(g)} \to 2CO_{2(g)}; \Delta H = -787 \ kJ$
$H_{2(g)} + 1/2 O_{2(g)} \to H_2O_{(l)}; \Delta H = -286 \ kJ$
$C_2H_{2(g)} + 2.5 O_{2(g)} \to 2CO_{2(g)} + H_2O_{(l)}; \Delta H = -1301 \ kJ$
Calculate the heat of formation of acetylene $(C_2H_{2(g)})$ in $kJ$.

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Given that:$2C_{(s)} + 2O_{2(g)} \to 2CO_{2(g)}; \Delta H = -787 \ kJ$$H_{2(g)} + 1/2 O_{2(g)} \to H_2O_{(l)}; \Delta H = -286 \ kJ$$C_2H_{2(g)} + 2.5 O_{2(g)} \to 2CO_{2(g)} + H_2O_{(l)}; \Delta H = -1301 \ kJ$Calculate the heat of formation of acetylene $(C_2H_{2(g)})$ in $kJ$.