Given that K = energy, V = velocity, T = time | vedclass

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Question

$\begin{array}{l}
Surface\,tension\, = \frac{F}{\ell } = \frac{F}{\ell } \cdot \frac{\ell }{\ell } \cdot \frac{{{T^2}}}{{{T^2}}}\
\left( {As,F.\ell

Vedclass · Accepted Answer

$[K\,{V^{ - 2}}{T^{ - 2}}]$

Vedclass · Answer

$\begin{array}{l}
Surface\,tension\, = \frac{F}{\ell } = \frac{F}{\ell } \cdot \frac{\ell }{\ell } \cdot \frac{{{T^2}}}{{{T^2}}}\
\left( {As,F.\ell  = K(energy);\frac{{{T^2}}}{{{\ell ^2}}} = {V^{ - 2}}} ight)\
Therefore,\,surface\,tension = \left[ {K{V^{ - 2}}{T^{ - 2}}} ight]
\end{array}$

Given that $K =$ energy, $V =$ velocity, $T =$ time. If they are chosen as the fundamental units, then what is dimensional formula for surface tension?

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