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(A) Consider the system consisting of both blocks $A$ and $B$ together.For the system to be in vertical equilibrium,the total downward gravitational f

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(A) Consider the system consisting of both blocks $A$ and $B$ together.For the system to be in vertical equilibrium,the total downward gravitational force must be balanced by the upward frictional force exerted by the wall on block $B$.The total weight of the system is $W_{total} = W_A + W_B = 20 \, N + 100 \, N = 120 \, N$.Let $f_B$ be the frictional force applied by the wall on block $B$.For vertical equilibrium,$\sum F_y = 0 \implies f_B - W_{total} = 0$.Therefore,$f_B = 120 \, N$.Thus,the frictional force applied by the wall on block $B$ is $120 \, N$.

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