A block of mass 2,kg moving on a horizontal s | vedclass

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Question

$a=\frac{- kx }{2}=\frac{-12 x }{2}=-6 x$

$\frac{ v d v }{ dx }=-6 x$

$\int \limits_{4}^{*} vdv =-\int \limits_{\frac{1}{2}}^{ s / 2} 6 xdx$

Vedclass · Accepted Answer

$2.0$

Vedclass · Answer

$a=\frac{- kx }{2}=\frac{-12 x }{2}=-6 x$

$\frac{ v d v }{ dx }=-6 x$

$\int \limits_{4}^{*} vdv =-\int \limits_{\frac{1}{2}}^{ s / 2} 6 xdx$

$\frac{ v ^{2}-4^{2}}{2}=-\frac{6}{2}\left[\left(\frac{3}{2}ight)^{2}-\left(\frac{1}{2}ight)^{2}ight]$

$v ^{2}-16=-6\left(\frac{9}{4}-\frac{1}{4}ight)$

$v ^{2}=16-6 	imes 2=4$

$V =2\,m / s$

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