Given below are two statements:
Statement $I$: Cross aldol condensation between two different aldehydes will always produce four different products.
Statement $II$: When semicarbazide reacts with a mixture of benzaldehyde and acetophenone under optimum pH,it forms a condensation product with acetophenone only.
In the light of the above statements,choose the correct answer from the options given below:

  • A
    Both Statement $I$ and Statement $II$ are false
  • B
    Statement $I$ is false but Statement $II$ is true
  • C
    Both Statement $I$ and Statement $II$ are true
  • D
    Statement $I$ is true but Statement $II$ is false

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Which of the following is the incorrect order for keto-enol stability?

Match the examples given in Column $I$ with the name of the reaction in Column $II$ and identify the correct matches.
Column $I$ $(Example)$ Column $II$ $(Reaction)$
$a$. $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$ Stephen's reaction
$b$. $C_6H_5CHO \xrightarrow{NaOH, \Delta} C_6H_5CH_2OH + C_6H_5COO^-Na^+$ Cannizzaro's reaction
$c$. $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$ Friedel-Crafts acylation
$d$. $R-CH_2-COOH \xrightarrow[H_2O]{Br_2/Red P} R-CH(Br)-COOH$ $HVZ$ reaction
$e$. $CH_3-CN \xrightarrow[\text{(ii) } H_2O/H^+]{\text{(i) } SnCl_2/HCl} CH_3CHO$ Stephen's reaction
$f$. $2 CH_3CHO \xrightarrow[\Delta]{NaOH} CH_3-CH=CHCHO$ Aldol condensation

When the compound $CH_3COCH_2CH_2CH_2CH_2CHO$ undergoes intramolecular aldol condensation,the major product formed is $:$

$Ph-CO-CH_3 \xrightarrow[H_2O]{Mg-Hg}$ Product. The main product is:

Match the example given in Column-$I$ with the name of the reaction in Column-$II$.
Column-$I$ (Example)Column-$II$ (Reaction)
$(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$$(1)$ Friedel-Crafts acylation
$(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$$(2)$ $HVZ$ reaction
$(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$$(3)$ Aldol condensation
$(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$$(4)$ Cannizzaro's reaction
$(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$$(5)$ Rosenmund's reduction
$(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$$(6)$ Stephen's reaction

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