$Ph-CO-CH_3 \xrightarrow[H_2O]{Mg-Hg}$ Product. The main product is:

Match the reactions in Column $I$ with appropriate options in Column $II$.

Column $I$	Column $II$
$A$. $Ph-N_2Cl + Ph-OH \xrightarrow{NaOH/H_2O, 0^{\circ}C} Ph-N=N-Ph-OH$	$p$. Racemic mixture
$B$. $Pinacol \xrightarrow{H_2SO_4} Pinacolone$	$q$. Addition reaction
$C$. $Ph-CO-CH_3 \xrightarrow{1. LiAlH_4, 2. H_3O^+} Ph-CH(OH)-CH_3$	$r$. Substitution reaction
$D$. $4-chlorocyclohexanethiol \xrightarrow{Base} Thiacycloheptane$	$s$. Coupling reaction
	$t$. Carbocation intermediate

The product obtained as a result of the reaction between acetone and chloroform is used as:

$A$ compound,containing only carbon,hydrogen,and oxygen,has a molecular weight of $44$. On complete oxidation,it is converted into a compound of molecular weight $60$. The original compound is:

$CH_3-CHO \xrightarrow{NaOH + Cl_2} A + HCOONa$. Product $A$ can be used as:

Arrange the following compounds in increasing order of their reactivity towards $HCN$:
$I$. Acetaldehyde
$II$. Acetone
$III$. Di-tert-butyl ketone
$IV$. Methyl-tert-butyl ketone