Given below are two statements:Statement I: A | vedclass

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(D) In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in $+2$ oxidation state with $d^8$ configuration. $H_2O$ is a weak field ligand,so it forms an octahedral complex w

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Statement $I$ is correct but Statement $II$ is incorrect

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(D) In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in $+2$ oxidation state with $d^8$ configuration. $H_2O$ is a weak field ligand,so it forms an octahedral complex with two unpaired electrons,which undergoes $d-d$ transition,making the solution green.In $[Ni(CN)_4]^{2-}$,$Ni$ is in $+2$ oxidation state with $d^8$ configuration. $CN^-$ is a strong field ligand,causing pairing of electrons. The complex is square planar and diamagnetic. However,it is yellow in colour due to charge transfer or specific electronic transitions,but it is often cited in textbooks as being colourless or having very pale colour compared to other complexes; however,strictly speaking,it is yellow. Given the standard context of such questions,Statement $I$ is correct and Statement $II$ is incorrect.

Given below are two statements:
Statement $I$: $A$ solution of $[Ni(H_2O)_6]^{2+}$ is green in colour.
Statement $II$: $A$ solution of $[Ni(CN)_4]^{2-}$ is colourless.
In the light of the above statements,choose the most appropriate answer from the options given below:

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Given below are two statements:Statement $I$: $A$ solution of $[Ni(H_2O)_6]^{2+}$ is green in colour.Statement $II$: $A$ solution of $[Ni(CN)_4]^{2-}$ is colourless.In the light of the above statements,choose the most appropriate answer from the options given below: