Given: $\sigma$ is the compressibility of water,$\rho$ is the density of water,and $K$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $h$ metre deep?

When a rubber ball is taken to the bottom of a sea of depth $1400 \,m$,its volume decreases by $2 \%$. The Bulk modulus of the rubber ball is .................. $\times 10^8 \,N/m^2$ [density of water is $1 \,g/cc$ and $g=10 \,m/s^2$].

$A$ solid sphere of radius $r$ made of a soft material of bulk modulus $K$ is surrounded by a liquid in a cylindrical container. $A$ massless piston of area $a$ floats on the surface of the liquid,covering the entire cross-section of the cylindrical container. When a mass $m$ is placed on the surface of the piston to compress the liquid,the fractional decrement in the radius of the sphere,$\left( \frac{dr}{r} \right)$ is:

$1\, m^3$ of water is brought inside a lake up to a depth of $200\, m$ from the surface. What will be the change in volume if the bulk modulus of elasticity of water is $22000\, \text{atm}$? (Given: density of water $\rho = 1\times10^3\, kg/m^3$, atmospheric pressure $P_0 = 10^5\, N/m^2$, and $g = 10\, m/s^2$)

Why is water more elastic than air?

The fractional compression $\left(\frac{\Delta V}{V}\right)$ of water at a depth of $2.5 \ km$ below the sea level is . . . . . . $\%$. Given: the Bulk modulus of water $B = 2 \times 10^9 \ N m^{-2}$,density of water $\rho = 10^3 \ kg m^{-3}$,and acceleration due to gravity $g = 10 \ m s^{-2}$.