Give the value of acceleration due to gravity | vedclass

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(B) The acceleration due to gravity $g'$ at a height $h$ above the surface of the earth is given by the formula $g' = g(1 - \frac{2h}{R})$,where $g =

Vedclass · Accepted Answer

$9.76$

Vedclass · Answer

(B) The acceleration due to gravity $g'$ at a height $h$ above the surface of the earth is given by the formula $g' = g(1 - \frac{2h}{R})$,where $g = 9.8\, m/s^2$ is the acceleration due to gravity at the surface,$h = 12\, km = 1.2 	imes 10^4\, m$,and $R = 6400\, km = 6.4 	imes 10^6\, m$ is the radius of the earth.Substituting the values:$g' = 9.8 	imes (1 - \frac{2 	imes 12}{6400})$$g' = 9.8 	imes (1 - \frac{24}{6400})$$g' = 9.8 	imes (1 - 0.00375)$$g' = 9.8 	imes 0.99625$$g' \approx 9.763\, m/s^2$.Thus,the value is approximately $9.76\, m/s^2$.

Give the value of acceleration due to gravity at height $12\, km$ from the surface of earth. (in $, m/s^2$)

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