Give the relation between shear modulus $(G)$ and Young's modulus $(Y)$ for an isotropic material.

The value of Poisson's ratio lies between

$A$ cylindrical wire of radius $1\, mm$,length $1\, m$,Young's modulus $Y = 2 \times 10^{11}\, N/m^2$,and Poisson's ratio $\mu = \pi / 10$ is stretched by a force of $100\, N$. What will be its new radius (in $, mm$)?

$A$ tension of $20 \,N$ is applied to a copper wire of cross-sectional area $0.01 \,cm^2$. The Young's modulus of copper is $1.1 \times 10^{11} \,N/m^2$ and the Poisson's ratio is $0.32$. The decrease in the cross-sectional area of the wire is:

$A$ uniform wire of length $10 \ m$ and diameter $0.6 \ mm$ is stretched by $6 \ mm$ with a certain force. If the Poisson's ratio of the material of the wire is $0.3$,then the change in diameter of the wire is

$A$ tension of $22 \,N$ is applied to a copper wire of cross-sectional area $0.02 \,cm^2$. Young's modulus of copper is $1.1 \times 10^{11} \,N/m^2$ and Poisson's ratio is $0.32$. The decrease in cross-sectional area will be: