Give the equations of two lines passing throu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The point $(2, 14)$ means $x = 2$ and $y = 14$.To find equations of lines passing through this point,we can use the form $ax + by = c$ such that $

Vedclass · Accepted Answer

x + y = $16$,7x - y = $0$; Infinitely many; Through a point,infinite lines can pass.

Vedclass · Answer

(A) The point $(2, 14)$ means $x = 2$ and $y = 14$.To find equations of lines passing through this point,we can use the form $ax + by = c$ such that $a(2) + b(14) = c$.$(i)$ If we take $a=1, b=1$,then $1(2) + 1(14) = 16$. So,$x + y = 16$ is one such equation.$(ii)$ If we take $a=7, b=-1$,then $7(2) - 1(14) = 14 - 14 = 0$. So,$7x - y = 0$ is another such equation.There are infinitely many such lines because an infinite number of lines can pass through a single point in a plane.

Give the equations of two lines passing through $(2, 14)$. How many more such lines are there,and why?

Similar Questions

Check whether $(4, 0)$ is a solution of the equation $x - 2y = 4$.

Find the value of $k$,if $x = 2$,$y = 1$ is a solution of the equation $2x + 3y = k$.

Yamini and Fatima,two students of Class $IX$ of a school,together contributed Rs. $100$ towards the Prime Minister's Relief Fund to help the earthquake victims. Write a linear equation which satisfies this data. (You may take their contributions as Rs. $x$ and Rs. $y$.) Draw the graph of the same.

Find four different solutions of the equation $x + 2y = 6.$

Draw the graph of $x + y = 7$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module