Give features of force on charge particle inside magnetic field.

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Magnetic force acted upon $q$ electric charge moving with $\vec{v}$ velocity in magnetic field $\overrightarrow{\mathrm{B}}$ is given by,

$\overrightarrow{\mathrm{F}_{\mathrm{m}}}=q(\vec{v} \times \overrightarrow{\mathrm{B}})$

$\therefore \mathrm{F}_{\mathrm{m}}=q v \mathrm{~B} \sin \theta$ where $\theta$ is angle between $\vec{v}$ and $\overrightarrow{\mathrm{B}}$.

Features :

$(i)$ It depends on $q, \vec{v}$ and $\overrightarrow{\mathrm{B}}$ (charge of the particle, the velocity and the magnetic field)

Force on a negative charge is opposite to that on a positive charge so we can write it as $\overrightarrow{\mathrm{F}}_{\mathrm{m}}=q(\overrightarrow{\mathrm{B}} \times \vec{v})$

$(ii)$ $\mathrm{F}_{\mathrm{m}}=q v \mathrm{~B} \sin \theta$ or $\overrightarrow{\mathrm{F}_{\mathrm{m}}}=q(\vec{v} \times \overrightarrow{\mathrm{B}})$ or $\left|\overrightarrow{\mathrm{F}_{\mathrm{m}}}\right|=q v \mathrm{~B} \sin \theta$ which is vector product of velocity and magnetic field. So, if $\theta=0^{\circ}$ or $\theta=180^{\circ}$, then $\mathrm{F}_{\mathrm{m}}=q v \mathrm{~B} \sin 0^{\circ}=0$ or $\mathrm{F}_{\mathrm{m}}=q v \mathrm{~B} \sin 180^{\circ}=0$

The force acts in a direction perpendicular to both the velocity and the magnetic field. Its direction is given by the screw rule or right hand rule as illustrated in figure $(a)$ and $(b)$.

Diagram $(a)$ is for positive charge and diagram $(b)$ is for negative charge.

$(iii)$ The magnetic force is zero if charge is not moving as then $v=0$.

$\therefore$ In magnetic force $\mathrm{F}_{\mathrm{m}}=q v \operatorname{Bsin} \theta v=0$, then

$\therefore \mathrm{F}_{\mathrm{m}}=0$

Thus, only a moving charge feels the magnetic force but static charge does not.

900-s51

Similar Questions

A negatively charged particle projected towards east is deflected towards north by a magnetic field. The field may be

A charged particle enters a magnetic field $H$ with its initial velocity making an angle of $45^\circ $ with $H$. The path of the particle will be

  • [AIIMS 1999]

A charged particle with specific charge $S$ moves undeflected through a region of space containing mutually perpendicular uniform electric and magnetic fields $E$ and $B$ . When electric field is switched off, the particle will move in a circular path of radius

An electron gun is placed inside a long solenoid of radius $\mathrm{R}$ on its axis. The solenoid has $\mathrm{n}$ turns/length and carries a current $I$. The electron gun shoots an electron along the radius of the solenoid with speed $v$. If the electron does not hit the surface of the solenoid, maximum possible value of ${v}$ is (all symbols have their standard meaning)

  • [JEE MAIN 2020]

If a particle of charge ${10^{ - 12}}\,coulomb$ moving along the $\hat x - $ direction with a velocity ${10^5}\,m/s$ experiences a force of ${10^{ - 10}}\,newton$ in $\hat y - $ direction due to magnetic field, then the minimum magnetic field is