Explain $\sigma$ and $\pi$ bonds,and mention the orbital overlapping involved in their formation.

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(N/A) The covalent bond formed by the overlapping of atomic orbitals can be classified into two types:
$\sigma$-bond: This type of covalent bond is formed by the end-to-end (head-on) overlapping of two atomic orbitals along the internuclear axis. This is also known as axial overlapping. It occurs in the following ways:
- $s-s$ overlapping: Overlapping of two half-filled $s$-orbitals.
- $s-p$ overlapping: Overlapping between a half-filled $s$-orbital and a half-filled $p$-orbital.
- $p-p$ overlapping: Overlapping of two half-filled $p$-orbitals along the internuclear axis.
$\pi$-bond: This type of covalent bond is formed by the sidewise (lateral) overlapping of atomic orbitals. In this case,the axes of the overlapping atomic orbitals remain parallel to each other and perpendicular to the internuclear axis.

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Similar Questions

Which of the following overlaps is incorrect (assuming $Z$-axis is the internuclear axis)?
$(A)$ $2p_y + 2p_y \to \pi$-bond formation
$(B)$ $2p_x + 2p_x \to \sigma$-bond formation
$(C)$ $3d_{xy} + 3d_{xy} \to \pi$-bond formation
$(D)$ $2s + 2p_y \to \pi$-bond formation
$(E)$ $3d_{xy} + 3d_{xy} \to \delta$-bond formation
$(F)$ $2p_z + 2p_z \to \sigma$-bond formation

Which of the following orbital overlaps is involved in the $HCl$ molecule?

Which of the following bonds is formed by the lateral overlap of $p-p$ orbitals?

$A$ carbon-carbon triple bond in ethyne $(HC \equiv CH)$ consists of:

Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: Zero orbital overlap is an out-of-phase overlap.
Reason $R$: It results due to different orientation/direction of approach of orbitals.
In the light of the above statements,choose the correct answer from the options given below.

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