Provide evidence that $[Co(NH_3)_5Cl]SO_4$ and $[Co(NH_3)_5SO_4]Cl$ are ionization isomers.
(N/A) Ionization isomers produce different ions in solution.
$1$. When $[Co(NH_3)_5Cl]SO_4$ is treated with $BaCl_2$ solution,it gives a white precipitate of $BaSO_4$,confirming the presence of $SO_4^{2-}$ ions in the ionization sphere:
$[Co(NH_3)_5Cl]SO_4 + Ba^{2+} \to [Co(NH_3)_5Cl]^{2+} + BaSO_4 \downarrow (\text{white precipitate})$.
$2$. When $[Co(NH_3)_5SO_4]Cl$ is treated with $AgNO_3$ solution,it gives a white precipitate of $AgCl$,confirming the presence of $Cl^-$ ions in the ionization sphere:
$[Co(NH_3)_5SO_4]Cl + Ag^+ \to [Co(NH_3)_5SO_4]^+ + AgCl \downarrow (\text{white precipitate})$.
Since they yield different ions in aqueous solution,they are ionization isomers.
$1$. When $[Co(NH_3)_5Cl]SO_4$ is treated with $BaCl_2$ solution,it gives a white precipitate of $BaSO_4$,confirming the presence of $SO_4^{2-}$ ions in the ionization sphere:
$[Co(NH_3)_5Cl]SO_4 + Ba^{2+} \to [Co(NH_3)_5Cl]^{2+} + BaSO_4 \downarrow (\text{white precipitate})$.
$2$. When $[Co(NH_3)_5SO_4]Cl$ is treated with $AgNO_3$ solution,it gives a white precipitate of $AgCl$,confirming the presence of $Cl^-$ ions in the ionization sphere:
$[Co(NH_3)_5SO_4]Cl + Ag^+ \to [Co(NH_3)_5SO_4]^+ + AgCl \downarrow (\text{white precipitate})$.
Since they yield different ions in aqueous solution,they are ionization isomers.
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The metal ion whose electronic configuration is not affected by the nature of the ligand and which gives a violet colour in non-luminous flame under hot condition in borax bead test is
Total number of isomers possible for the complex $[Co(en)_2Cl_2]$ is
Medium
View SolutionIdentify the pair of complexes that have the same magnetic moment (spin-only value).
Difficult
View Solution$STATEMENT-1$: The geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ are optically inactive.
$STATEMENT-2$: Both geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ possess a plane of symmetry.
$STATEMENT-2$: Both geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ possess a plane of symmetry.
Consider the following metal complexes:
$1. [Co(NH_3)_6]^{3+}$
$2. [CoCl(NH_3)_5]^{2+}$
$3. [Co(CN)_6]^{3-}$
$4. [Co(NH_3)_5(H_2O)]^{3+}$
The spin-only magnetic moment value of the complex that absorbs light with the shortest wavelength is $B.M.$ (Nearest integer).
$1. [Co(NH_3)_6]^{3+}$
$2. [CoCl(NH_3)_5]^{2+}$
$3. [Co(CN)_6]^{3-}$
$4. [Co(NH_3)_5(H_2O)]^{3+}$
The spin-only magnetic moment value of the complex that absorbs light with the shortest wavelength is $B.M.$ (Nearest integer).
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