Identify the pair of complexes that have the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic moment (spin-only) is given by $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Two complexes have the same

Vedclass · Accepted Answer

$[Cr(H_2O)_6]^{2+}, [Fe(H_2O)_6]^{2+}$

Vedclass · Answer

(B) The magnetic moment (spin-only) is given by $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Two complexes have the same magnetic moment if they have the same number of unpaired electrons $(n)$.$1$. $[Cr(H_2O)_6]^{2+}$: $Cr^{2+}$ is $3d^4$. $H_2O$ is a weak field ligand,so $n = 4$.$2$. $[CoCl_4]^{2-}$: $Co^{2+}$ is $3d^7$. $Cl^-$ is a weak field ligand,so $n = 3$.$3$. $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $3d^6$. $H_2O$ is a weak field ligand,so $n = 4$.$4$. $[Mn(H_2O)_6]^{2+}$: $Mn^{2+}$ is $3d^5$. $H_2O$ is a weak field ligand,so $n = 5$.Comparing the values of $n$:$[Cr(H_2O)_6]^{2+}$ has $n = 4$ and $[Fe(H_2O)_6]^{2+}$ has $n = 4$.Therefore,they have the same magnetic moment.

Identify the pair of complexes that have the same magnetic moment (spin-only value).

Similar Questions

Which of the following compounds has a magnetic moment of $\sqrt{15} \ B.M.$?

The complexes given below show:

Select the correct statement about the given square planar complex.

Which of the following species is paramagnetic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module