The pairs of species of oxygen and their magn | vedclass

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Question

$\mathrm{O}_{2}^{+}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \sigma 2 \mathrm{pz}^{2}\left(\pi 2 \mathrm{px}^{2}=\pi 2 \mathrm{

Vedclass · Accepted Answer

$O_2^+ , O_2$ - Both paramagnetic

Vedclass · Answer

$\mathrm{O}_{2}^{+}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \sigma 2 \mathrm{pz}^{2}\left(\pi 2 \mathrm{px}^{2}=\pi 2 \mathrm{py}^{2}\right)\left(\pi^{*} 2 \mathrm{px}^{1}\right)$

$\mathrm{O}_{2}=\mathrm{KK} \sigma 2 \mathrm{s}^{2} \sigma^{*} 2 \mathrm{s}^{2} \sigma 2 \mathrm{pz}^{2}\left(\pi 2 \mathrm{px}^{2}=\pi 2 \mathrm{py}^{2}\right)\left(\pi^{*} 2 \mathrm{px}^{1}=\pi^{*} 2 \mathrm{py}^{1}\right)$

$\mathrm{O}_{2}$ and $\mathrm{O}_{2}^{+}$ contain unpaired electron in $\pi^{*}$ ABMO so paramagnetic.

$List-I$	$List-II$
$(A)$ $\Psi_{ MO }=\Psi_{ A }-\Psi_{ B }$	$(I)$ Dipole moment
$(B)$ $\mu=Q \times I$	$(II)$ Bonding molecular orbital
$(C)$ $\frac{N_{b}-N_{a}}{2}$	$(III)$ Anti-bonding molecualr orbital
$(D)$ $\Psi_{ MO }=\Psi_{ A }+\Psi_{ B }$	$(IV)$ Bond order

The pairs of species of oxygen and their magnetic behaviour are noted below. Which of the following presents the correct description ?

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