Give difference : Bonding molecular orbital a | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Bonding Molecular Orbitals ($BMO$)
			
			Antibonding Molecular Orbitals ($ABMO$)
			
		
		
			It is in short $BMO$. Its wave functi

Vedclass · Accepted Answer

Vedclass · Answer

Bonding Molecular Orbitals ($BMO$)
			
			Antibonding Molecular Orbitals ($ABMO$)
			
		
		
			It is in short $BMO$. Its wave function is express by $\psi_{	ext {MO }}$.
			
			It is in short $ABMO$ its wave function is express by $\psi_{	ext {MO }}^{*}$
			
		
		
			
			Definition: They are formed by the addition of atomic orbital is known of $BMO$.

			$\psi_{\mathrm{MO}}=\psi_{\mathrm{A}}+\psi_{\mathrm{B}}$
			
			
			Definition : They are formed by the substractive effect of the atomic orbitals is known $ABMO.$
			
		
		
			Qualitative, the formation of $BMO$ can be understood in terms of the constructive of the electron waves of the combining atoms and reinforce each other.
			
			$\psi^{*}$ MO $=\psi_{	ext {A }}$ - $\psi_{	ext {B }}$ Qualitative, the formation of $ABMO$ can be under- stood in terms of the destructive interference of the electron waves of the combining atoms and cancel each other.
			
		
		
			As a result, the electron density in a $BMO$ is located between the nuclei of the bonded atoms because of which the repulsing between the nuclei is very less.
			
			In case of an $ABMO$, most of the electron density is located away from the space between the nuclei

			 
			
		
		
			The nodal plane is not present in $BMO.$
			
			There is a nodal plane (on which electron density is zero) between the nuclei.
			
		
		
			Electron placed in a $BMO$ tend to hold the nuclei together and stabilize a molecule.
			The electron placed in the $ABMO$ destabilize the molecule.
		
		
			A $BMO$ always possesses lower energy than either the atomic orbitals that have combined to from it.
			The $ABMO$ always possesses higher of energy than either of the atomic orbitals that have combined to form it
		
		
			In $BMO$, the repulsion between electron-electron is less than the attraction between electron and nuclei, So energy is less of $BMO$.
			In$ABMO$, repulsion of electron is more than the attraction between the electrons and the nuclei, which causes a not increase energy.
		
		
			BMO is stable. e.g. $\sigma$ and $\pi$ are $BMO$.
			$\mathrm{ABMO}$ is unstable. e.g. $\sigma^{*}$ and $\pi^{*}$ are $ABMO$.

List$-I$	List$-II$
$(a)$ $Ne _{2}$	$(i)$ $1$
$(b)$ $N _{2}$	$(ii)$ $2$
$(c)$ $F _{2}$	$(iii)$ $0$
$(d)$ $O _{2}$	$(iv)$ $3$

Give difference : Bonding molecular orbital and antibonding molecular orbitals.

Similar Questions

Which of the following is paramagnetic as well as it has fractional bond order ?

Match List$-I$ with List$-II.$

List$-I$ List$-II$

$(a)$ $Ne _{2}$ $(i)$ $1$

$(b)$ $N _{2}$ $(ii)$ $2$

$(c)$ $F _{2}$ $(iii)$ $0$

$(d)$ $O _{2}$ $(iv)$ $3$

Choose the correct answer from the options given below:

Which of the following species would be expected paramagnetic

Which of the following contains $(2C -1e^-)$ bond

If Hund's Rule does not hold good, then which of the following pairs is diamagnetic

Bonding Molecular Orbitals ($BMO$)	Antibonding Molecular Orbitals ($ABMO$)
It is in short $BMO$. Its wave function is express by $\psi_{\text {MO }}$.	It is in short $ABMO$ its wave function is express by $\psi_{\text {MO }}^{*}$
Definition: They are formed by the addition of atomic orbital is known of $BMO$. $\psi_{\mathrm{MO}}=\psi_{\mathrm{A}}+\psi_{\mathrm{B}}$	Definition : They are formed by the substractive effect of the atomic orbitals is known $ABMO.$
Qualitative, the formation of $BMO$ can be understood in terms of the constructive of the electron waves of the combining atoms and reinforce each other.	$\psi^{*}$ MO $=\psi_{\text {A }}$ - $\psi_{\text {B }}$ Qualitative, the formation of $ABMO$ can be under- stood in terms of the destructive interference of the electron waves of the combining atoms and cancel each other.
As a result, the electron density in a $BMO$ is located between the nuclei of the bonded atoms because of which the repulsing between the nuclei is very less.	In case of an $ABMO$, most of the electron density is located away from the space between the nuclei
The nodal plane is not present in $BMO.$	There is a nodal plane (on which electron density is zero) between the nuclei.
Electron placed in a $BMO$ tend to hold the nuclei together and stabilize a molecule.	The electron placed in the $ABMO$ destabilize the molecule.
A $BMO$ always possesses lower energy than either the atomic orbitals that have combined to from it.	The $ABMO$ always possesses higher of energy than either of the atomic orbitals that have combined to form it
In $BMO$, the repulsion between electron-electron is less than the attraction between electron and nuclei, So energy is less of $BMO$.	In$ABMO$, repulsion of electron is more than the attraction between the electrons and the nuclei, which causes a not increase energy.
BMO is stable. e.g. $\sigma$ and $\pi$ are $BMO$.	$\mathrm{ABMO}$ is unstable. e.g. $\sigma^{}$ and $\pi^{}$ are $ABMO$.