The general configuration of the outermost an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. For $n = 4$ and $x = 5$,the configuration becomes $3s^2 3p^6 3d^5 4s^2$. This co

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) Given the configuration: $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. For $n = 4$ and $x = 5$,the configuration becomes $3s^2 3p^6 3d^5 4s^2$. This corresponds to the element Manganese $(Mn)$,which has an atomic number of $25$. The total number of electrons is calculated by summing the electrons in all shells: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2$. Total electrons $= 2 + 2 + 6 + 2 + 6 + 5 + 2 = 25$. Since the number of protons equals the number of electrons in a neutral atom,the number of protons is $25$.

The general configuration of the outermost and penultimate shell is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. If $n = 4$ and $x = 5$,then the number of protons in the nucleus will be:

Similar Questions

For an electron in the $d$-orbital,the orbital angular momentum is

Explain $2p$ orbitals.

Which of the following is not correct for the electron distribution in the ground state for $4s$ and $3d$ orbitals?

Which of the following sets of quantum numbers $(n, l, m, s)$ is incorrect?

Electronic configuration of $C$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module