Explain $2p$ orbitals.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
If $n=2$ and $l=1$,then it is a $2p$ orbital. The number of orbitals is given by $2l+1 = 2(1)+1 = 3$.
These three $2p$ orbitals have magnetic quantum numbers $(m_l): +1, 0, -1$. These values can be assigned to any orbital,and $p_x$ can be given any of these values.
Based on their orientation along the axes,these orbitals are known as $2p_x, 2p_y, 2p_z$.
The number of radial nodes in $2p$ orbitals is zero as per the formula $(n-l-1) = (2-1-1) = 0$. However,the number of angular nodes (nodal planes) is one. At the nodal plane where the two lobes meet,the electron density is zero.

Explore More

Similar Questions

The number of nodal planes a $d$ orbital has is:

What would be the electronic configuration of $Cs (Z=55)$ in each case?
$(a)$ If there were three possibilities of the electron spin.
$(b)$ If the quantum number,$l$,could have the value $n$,and if all the rules governing electron configuration were otherwise valid.

Which of the following statements is not correct?

The orbital angular momentum of an electron in an $s$ orbital is

The number of electrons present in all the completely filled subshells having $n=4$ and $s=+\frac{1}{2}$ is . . . . . . . (Where $n=$ principal quantum number and $s=$ spin quantum number)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo