A took two loans altogether of ₹ 1200 from B | vedclass

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(D) Let the amount borrowed by $A$ from $B$ be ₹ $x$.Then,the amount borrowed from $C$ is ₹ $(1200 - x)$.The simple interest formula is $SI = \frac{P

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₹ $800$ from $B$

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(D) Let the amount borrowed by $A$ from $B$ be ₹ $x$.Then,the amount borrowed from $C$ is ₹ $(1200 - x)$.The simple interest formula is $SI = \frac{P 	imes R 	imes T}{100}$.According to the question,the total interest paid in one year is ₹ $172$:$\frac{x 	imes 14 	imes 1}{100} + \frac{(1200 - x) 	imes 15 	imes 1}{100} = 172$Multiply the entire equation by $100$:$14x + 15(1200 - x) = 17200$$14x + 18000 - 15x = 17200$$-x + 18000 = 17200$$x = 18000 - 17200$$x = 800$Therefore,$A$ borrowed ₹ $800$ from $B$.

$A$ took two loans altogether of ₹ $1200$ from $B$ and $C$. $B$ claimed $14 \%$ simple interest per annum,while $C$ claimed $15 \%$ per annum. The total interest paid by $A$ in one year was ₹ $172$. How much did $A$ borrow from $B$?

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