Four smooth steel balls of equal mass at rest | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a head-on elastic collision between two bodies of equal mass,the velocities of the bodies are interchanged.Let the masses of the four balls be

Vedclass · Accepted Answer

$0.4$

Vedclass · Answer

(A) In a head-on elastic collision between two bodies of equal mass,the velocities of the bodies are interchanged.Let the masses of the four balls be $m_1 = m_2 = m_3 = m_4 = m$.The first ball has an initial velocity $v_1 = 0.4 \, m/s$ and the others are at rest $(v_2 = v_3 = v_4 = 0)$.When the first ball collides with the second,they exchange velocities: the first ball comes to rest,and the second ball moves with $v_2 = 0.4 \, m/s$.When the second ball collides with the third,they exchange velocities: the second ball comes to rest,and the third ball moves with $v_3 = 0.4 \, m/s$.This process continues until the last ball is hit.Therefore,the last ball will move with the velocity of the first ball,which is $0.4 \, m/s$.

Similar Questions

$A$ block rests on a rough inclined plane making an angle of $30^o$ with the horizontal. The coefficient of static friction between the block and the plane is $0.8$. If the frictional force on the block is $10 \, N$,the mass of the block (in $kg$) is (take $g = 10 \, m/s^2$)

In a $\triangle ABC$,the expression $\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4b^2c^2}$ is equal to:

In the photoelectric effect,if the work functions of $Li$,$Na$,and $Rb$ are $2.41 \ eV$,$2.30 \ eV$,and $2.09 \ eV$ respectively,what could be the approximate work function of $K$ in $eV$?

The first minima due to a single slit diffraction is at $\theta = 30^o$ for a light of wavelength $5000\,\mathring{A}$. The width of the slit is:

The branched tree-like structure present in the cerebellum is known as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module