In a $\triangle ABC$,the expression $\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4b^2c^2}$ is equal to:

  • A
    $\cos^2 A$
  • B
    $\cos^2 B$
  • C
    $\sin^2 A$
  • D
    $\sin^2 B$

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