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(D) The number of possible emission lines when an electron transitions from an excited state $n$ to lower energy states is given by the formula:$N = \

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$6$

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(D) The number of possible emission lines when an electron transitions from an excited state $n$ to lower energy states is given by the formula:$N = \frac{n(n - 1)}{2}$Here,the highest energy level is $n = 4$.Substituting $n = 4$ into the formula:$N = \frac{4(4 - 1)}{2} = \frac{4 	imes 3}{2} = \frac{12}{2} = 6$Thus,there are $6$ possible emission lines corresponding to the transitions: $4 	o 3, 4 	o 2, 4 	o 1, 3 	o 2, 3 	o 1,$ and $2 	o 1$.

The four lowest energy levels of an $H$-atom are shown in the figure. The number of possible emission lines would be

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