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(A) The magnification $m$ of an astronomical telescope is given by the formula $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective

Vedclass · Accepted Answer

$100 \, cm, 0.3 \, cm$

Vedclass · Answer

(A) The magnification $m$ of an astronomical telescope is given by the formula $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.To obtain the maximum possible magnification,the ratio $\frac{f_o}{f_e}$ must be maximized.This requires $f_o$ to be the maximum available focal length and $f_e$ to be the minimum available focal length.Given focal lengths are $100 \, cm, 10 \, cm, 4 \, cm$,and $0.3 \, cm$.Thus,we choose $f_o = 100 \, cm$ and $f_e = 0.3 \, cm$.

Four convergent lenses have focal lengths $100 \, cm, 10 \, cm, 4 \, cm$ and $0.3 \, cm$. For a telescope with maximum possible magnification,we choose the lenses of focal lengths:

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