The capacitors of capacity $C_1$ and $C_2$ are connected in parallel,then the equivalent capacitance is:

  • A
    $C_1 + C_2$
  • B
    $\frac{C_1 C_2}{C_1 + C_2}$
  • C
    $\frac{C_1}{C_2}$
  • D
    $\frac{C_2}{C_1}$

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