Formic acid on heating with concentrated H_2S | vedclass

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Question

(A) The reaction of formic acid $(HCOOH)$ with concentrated $H_2SO_4$ is a dehydration reaction:$HCOOH \xrightarrow{Conc. H_2SO_4, 373 \ K} H_2O + CO$

Vedclass · Accepted Answer

$X=2,0; Y=1,2$

Vedclass · Answer

(A) The reaction of formic acid $(HCOOH)$ with concentrated $H_2SO_4$ is a dehydration reaction:$HCOOH \xrightarrow{Conc. H_2SO_4, 373 \ K} H_2O + CO$Here,$X$ is $H_2O$ (water) and $Y$ is $CO$ (carbon monoxide).In $H_2O$ $(X)$,there are two $O-H$ single bonds,so it has $2 \sigma$ bonds and $0 \pi$ bonds.In $CO$ $(Y)$,the structure is $C \equiv O$,which consists of $1 \sigma$ bond and $2 \pi$ bonds.Therefore,for $X$ $(H_2O)$,the count is $2 \sigma, 0 \pi$ and for $Y$ $(CO)$,the count is $1 \sigma, 2 \pi$.Thus,the correct option is $A$.

Formic acid on heating with concentrated $H_2SO_4$ at $373 \ K$ gives $X$,a colourless substance and $Y$,a good reducing agent. The number of $\sigma$ and $\pi$ bonds in $X$ and $Y$ are respectively:

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