For the series LCR circuit shown in the figur | vedclass

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(A) The resonance angular frequency $\omega$ is given by the formula: $\omega = \frac{1}{\sqrt{LC}}$.Given $L = 8 \, mH = 8 	imes 10^{-3} \, H$ and $

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$2500 \, rad/s$,$5\sqrt{2} \, A$

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(A) The resonance angular frequency $\omega$ is given by the formula: $\omega = \frac{1}{\sqrt{LC}}$.Given $L = 8 \, mH = 8 	imes 10^{-3} \, H$ and $C = 20 \, \mu F = 20 	imes 10^{-6} \, F$.Substituting these values: $\omega = \frac{1}{\sqrt{8 	imes 10^{-3} 	imes 20 	imes 10^{-6}}} = \frac{1}{\sqrt{160 	imes 10^{-9}}} = \frac{1}{\sqrt{16 	imes 10^{-8}}} = \frac{1}{4 	imes 10^{-4}} = 2500 \, rad/s$.At resonance,the impedance $Z = R = 44 \, \Omega$.The $RMS$ current $I_{rms} = \frac{V_{rms}}{R} = \frac{220}{44} = 5 \, A$.The amplitude of the current (peak current) $I_0 = I_{rms} \sqrt{2} = 5\sqrt{2} \, A$.

For the series $LCR$ circuit shown in the figure,what is the resonance angular frequency and the amplitude of the current at the resonating frequency? The source voltage is given as $220 \, V$ ($RMS$ value).

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