For the sequence of reactions A xrightarrow{C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of a Grignard reagent $(RMgX)$ with a carbonyl compound followed by hydrolysis yields an alcohol. To obtain $	ext{tert-pentyl alcoho

Vedclass · Accepted Answer

acetone

Vedclass · Answer

(C) The reaction of a Grignard reagent $(RMgX)$ with a carbonyl compound followed by hydrolysis yields an alcohol. To obtain $	ext{tert-pentyl alcohol}$ $(CH_3CH_2C(CH_3)_2OH)$,we need to react a ketone with a Grignard reagent. Here,the Grignard reagent is $C_2H_5MgI$ (ethylmagnesium iodide). When $C_2H_5MgI$ reacts with $A$ (acetone,$CH_3COCH_3$),the nucleophilic ethyl group attacks the carbonyl carbon of acetone. $CH_3COCH_3 + C_2H_5MgI ightarrow CH_3C(OMgI)(CH_3)(C_2H_5)$. Upon hydrolysis with $H_2O/H^+$,this forms $CH_3C(OH)(CH_3)(C_2H_5)$,which is $2-$methylbutan$-2-$ol,commonly known as $	ext{tert-pentyl alcohol}$. Therefore,compound $A$ is acetone.

For the sequence of reactions $A$ $\xrightarrow{C_2H_5MgI} B$ $\xrightarrow{H_2O / H^{+}} \text{tert-pentyl alcohol}$. The compound $A$ in the sequence is

Similar Questions

Consider the following sequence of reactions.
$1$-methylindene $\xrightarrow[NaHSO_3]{OsO_4} A$ $\xrightarrow[2. NaOH, \text{heat}]{1. HIO_4} B$
The final product $(B)$ is

The Clemmensen reduction of acetone yields

$A$ strong base can abstract an $\alpha$-hydrogen from

The major products formed in the following reaction sequence $A$ and $B$ are :

The reduction of carbonyl compounds with aluminum isopropoxide in excess of isopropanol is known as the Meerwein-Ponndorf-Verley $(MPV)$ reduction. What is the final product when cyclohex$-2-$enone undergoes selective reduction using this method?

Vedclass Test Series

Exam Paper Generator

Online Exam Module