$A$ strong base can abstract an $\alpha$-hydrogen from

The products $(A)$ and $(B)$ are formed by the following reaction sequence:
$1$. $\text{NH}_2\text{OH}$
$2$. $\text{H}^+, \Delta$
$3$. $\text{LiAlH}_4$
Identify the products $(A)$ and $(B)$.

The reagent used in the Wolff-Kishner reduction is

In the given reaction,
$Cyclohexanone \xrightarrow[(ii) \text{ heat}]{(i) \text{ } OH^-} 'P'$
The number of $\pi$ electrons present in the product $'P'$ is $....$

The conversion shown in the image can be achieved by:

$A$ carbonyl compound $P$,which gives a positive iodoform test,undergoes reaction with $MeMgBr$ followed by dehydration to give an olefin $Q$. Ozonolysis of $Q$ leads to a dicarbonyl compound $R$,which undergoes intramolecular aldol reaction to give predominantly $S$.
$P$ $\xrightarrow[\substack{2. H^{+}, H_2 O \\ 3. H_2 SO_4, \Delta}]{1. MeMgBr} Q$ $\xrightarrow[2. Zn, H_2 O]{1. O_3} R$ $\xrightarrow[2. \Delta]{1. OH^{-}} S$
$1.$ The structure of the carbonyl compound $P$ is
$2.$ The structures of the products $Q$ and $R$,respectively,are
$3.$ The structure of the product $S$ is
Give the answer for questions $1, 2$ and $3.$