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(B) Radius of the cylinder $=$ radius of each cone $= r = 10 \,cm$.Height of the cylinder $H = 40 \,cm$.Slant height of the cone $l = 26 \,cm$.For the

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$17.6$

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(B) Radius of the cylinder $=$ radius of each cone $= r = 10 \,cm$.Height of the cylinder $H = 40 \,cm$.Slant height of the cone $l = 26 \,cm$.For the cone,$l^2 = r^2 + h^2$,where $h$ is the height of the cone.$h = \sqrt{l^2 - r^2} = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24 \,cm$.Volume of the combined container $=$ Volume of the cylinder $+ 2 	imes$ Volume of the cone.Volume $= \pi r^2 H + 2 	imes (\frac{1}{3} \pi r^2 h) = \pi r^2 (H + \frac{2}{3} h)$.Substituting the values: Volume $= \frac{22}{7} 	imes 10^2 	imes (40 + \frac{2}{3} 	imes 24) = \frac{22}{7} 	imes 100 	imes (40 + 16) = \frac{22}{7} 	imes 100 	imes 56$.Volume $= 22 	imes 100 	imes 8 = 17600 \,cm^3$.Since $1000 \,cm^3 = 1 \,litre$,the volume in litres is $\frac{17600}{1000} = 17.6 \,litres$.Thus,the model can contain $17.6 \,litres$ of water.

For the science fair,a student prepared a model in the shape of a cylinder with radius $10 \,cm$ and height $40 \,cm$,closed at both ends by cones with slant height $26 \,cm$. How many litres of water can it contain?

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