For the reaction ${H_2}(g) + B{r_2}(g) \to 2HBr(g)$, the experimental data suggest, rate $ = K[{H_2}]{[B{r_2}]^{1/2}}$. The molecularity and order of the reaction are respectively

  • A

    $2,\,\frac{3}{2}$

  • B

    $\frac{3}{2},\,\frac{3}{2}$

  • C

    $1, 1$

  • D

    $1,\,\frac{1}{2}$

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