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(D) $1$. For carbocations $(Ph_3C^{+} > Ph_2CH^{+} > PhCH_2^{+})$,stability increases with the number of phenyl groups due to resonance stabilization.

Vedclass · Accepted Answer

$Ph_3C^{+} < Ph_2CH^{+} < PhCH_2^{+}$

Vedclass · Answer

(D) $1$. For carbocations $(Ph_3C^{+} > Ph_2CH^{+} > PhCH_2^{+})$,stability increases with the number of phenyl groups due to resonance stabilization.$2$. For carbanions $(Ph_3C^{-} $3$. For free radicals $(Ph_3C^{\bullet} > Ph_2CH^{\bullet} > PhCH_2^{\bullet})$,stability increases with the number of phenyl groups due to resonance.$4$. Option $D$ is incorrect because the stability order of carbocations is $Ph_3C^{+} > Ph_2CH^{+} > PhCH_2^{+}$.

Which of the following represents the incorrect stability order?

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What is the hybridization state of a carbocation?

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