For the finite $A.P.$ $5, 9, 13, \ldots, 101$,find the $9^{th}$ term from the end.

  • A
    $70$
  • B
    $69$
  • C
    $75$
  • D
    $55$

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Find four numbers in $A.P.$ such that their sum is $36$ and the product of means ($2^{nd}$ and $3^{rd}$ term) exceeds the product of extremes ($1^{st}$ and $4^{th}$ term) by $32.$

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The $n^{th}$ term of an $A.P.$ is given by $T_{n} = 10 - 6n$. Find the sum of the first $n$ terms of the $A.P.$

Find the sum of the series: $3 + 7 + 11 + \ldots + 119$.

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