For the curve $x^{2}+4xy+8y^{2}=64$,the tangents are parallel to the $x$-axis only at the points

  • A
    $(0, 2\sqrt{2})$ and $(0, -2\sqrt{2})$
  • B
    $(8, -4)$ and $(-8, 4)$
  • C
    $(8\sqrt{2}, -2\sqrt{2})$ and $(-8\sqrt{2}, 2\sqrt{2})$
  • D
    $(9, 0)$ and $(-8, 0)$

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Consider the lines $L_1$ and $L_2$ defined by $L_1: x \sqrt{2} + y - 1 = 0$ and $L_2: x \sqrt{2} - y + 1 = 0$. For a fixed constant $\lambda$,let $C$ be the locus of a point $P$ such that the product of the distance of $P$ from $L_1$ and the distance of $P$ from $L_2$ is $\lambda^2$. The line $y = 2x + 1$ meets $C$ at two points $R$ and $S$,where the distance between $R$ and $S$ is $\sqrt{270}$. Let the perpendicular bisector of $RS$ meet $C$ at two distinct points $R^{\prime}$ and $S^{\prime}$. Let $D$ be the square of the distance between $R^{\prime}$ and $S^{\prime}$.
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