For the complexes showing the square pyramidal structure,the $d-$orbital involved in the hybridisation is

  • A
    $d_{x^2-y^2}$
  • B
    $d_{z^2}$
  • C
    $d_{xy}$
  • D
    $d_{xz}$

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Similar Questions

Which of the following is not a square planar complex?

Which of the following sequences of hybridisation, geometry, and magnetic nature are correct for the given coordination compounds?
$A.$ $[NiCl_4]^{2-}$ – $sp^3$, tetrahedral, paramagnetic  
$B.$ $[Ni(NH_3)_6]^{2+}$ – $sp^3d^2$, octahedral, paramagnetic  
$C.$ $[Ni(CO)_4]$ – $sp^3$, tetrahedral, paramagnetic  
$D.$ $[Ni(CN)_4]^{2-}$ – $dsp^2$, square planar, diamagnetic  
Choose the correct answer from the options given below:

Which of the following statements is incorrect for $K_3[CoF_6]$?

How many electrons are present in the $3d$ orbital of the tetrahedral $K_2[NiCl_4]$ complex?

Match the correct option.
$A$. $[CoF_6]^{3-}$$M$. $sp^3d^2$,paramagnetic
$B$. $[Mn(CN)_6]^{3-}$$N$. $sp^3d^2$,diamagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$$O$. $d^2sp^3$,paramagnetic
$D$. $[Zn(H_2O)_6]^{2+}$$P$. $d^2sp^3$,diamagnetic

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