(B) In the complex $K_2[NiCl_4]$,let the oxidation state of $Ni$ be $x$. $2(+1) + x + 4(-1) = 0$ $\Rightarrow 2 + x - 4 = 0$ $\Rightarrow x = +2$. The

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(B) In the complex $K_2[NiCl_4]$,let the oxidation state of $Ni$ be $x$. $2(+1) + x + 4(-1) = 0$ $\Rightarrow 2 + x - 4 = 0$ $\Rightarrow x = +2$. The atomic number of $Ni$ is $28$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$. Thus,the number of electrons in the $3d$ orbital is $8$.

Class 12 Chemistry Coordination Compounds Hybridisation and Geometry

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How many electrons are present in the $3d$ orbital of the tetrahedral $K_2[NiCl_4]$ complex?

GUJCET 2009 All GUJCET

A
$10$ electrons
B
$8$ electrons
C
$6$ electrons
D
$7$ electrons

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How many electrons are present in the $3d$ orbital of the tetrahedral $K_2[NiCl_4]$ complex?

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$[FeF_6]^{3-}$ has $Fe$ atom . . . . . . hybridised with unpaired . . . . . . electrons.

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