For given systen T_2 ....... | vedclass

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Question

${T_1}\cos {	heta _1} = mg$&hellip;&hellip;(i)

${T_1}\sin {	heta _1} = - mg$&hellip;..(ii)

$T_1^2\left( {{{\sin }^2}{	heta _1} + {{\cos }^2}{

Vedclass · Accepted Answer

$\sqrt 5 \,mg$

Vedclass · Answer

${T_1}\cos {	heta _1} = mg$&hellip;&hellip;(i)

${T_1}\sin {	heta _1} = - mg$&hellip;..(ii)

$T_1^2\left( {{{\sin }^2}{	heta _1} + {{\cos }^2}{	heta _1}} ight) = 2{\left( {mg} ight)^2}$

$	herefore $ ${T_1} = \sqrt 2 mg$

${T_2}\cos {	heta _2} = mg + {T_1}\cos {	heta _1}$

${T_2}\cos {	heta _2} = mg + \sqrt 2 mg\,\cos 45^\circ $

${T_2}\cos {	heta _2} = 2mg$&hellip;..(i)

${T_2}\sin {	heta _2} = {T_1}\sin {	heta _1}$

$ = \sqrt 2 mg\,\sin 45^\circ $

${T_2}\sin {	heta _2} = mg$&hellip;..(ii)

$T_2^2 = 5{(mg)^2}$ or ${T_2} = \sqrt 5 mg$

For given systen $T_2$ .......

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