For an object projected from ground with speed $u$ horizontal range is two times the maximum height attained by it. The horizontal range of object is ..........
For an object projected from ground with speed $u$ horizontal range is two times the maximum height attained by it. The horizontal range of object is ..........
- A
$\frac{2 u^2}{3 g}$
- B
$\frac{3 u^2}{4 g}$
- C
$\frac{3 u^2}{2 g}$
- D
$\frac{4 u^2}{5 g}$
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A cricketer hits a ball with a velocity $25\,\,m/s$ at ${60^o}$ above the horizontal. How far above the ground it passes over a fielder $50 m$ from the bat ........ $m$ (assume the ball is struck very close to the ground)
A cricketer hits a ball with a velocity $25\,\,m/s$ at ${60^o}$ above the horizontal. How far above the ground it passes over a fielder $50 m$ from the bat ........ $m$ (assume the ball is struck very close to the ground)
A projectile is projected from ground with initial velocity $\vec u\, = \,{u_0}\hat i\, + \,{v_0}\hat j\,$. If acceleration due to gravity $(g)$ is along the negative $y-$ direction then find maximum displacement in $x-$ direction
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Trajectory of particle in a projectile motion is given as $y=x-\frac{x^2}{80}$. Here, $x$ and $y$ are in metre. For this projectile motion match the following with $g=10\,m / s ^2$.
$Column-I$
$Column-II$
$(A)$ Angle of projection
$(p)$ $20\,m$
$(B)$ Angle of velocity with horizontal after $4\,s$
$(q)$ $80\,m$
$(C)$ Maximum height
$(r)$ $45^{\circ}$
$(D)$ Horizontal range
$(s)$ $\tan ^{-1}\left(\frac{1}{2}\right)$
Trajectory of particle in a projectile motion is given as $y=x-\frac{x^2}{80}$. Here, $x$ and $y$ are in metre. For this projectile motion match the following with $g=10\,m / s ^2$.
| $Column-I$ | $Column-II$ |
| $(A)$ Angle of projection | $(p)$ $20\,m$ |
| $(B)$ Angle of velocity with horizontal after $4\,s$ | $(q)$ $80\,m$ |
| $(C)$ Maximum height | $(r)$ $45^{\circ}$ |
| $(D)$ Horizontal range | $(s)$ $\tan ^{-1}\left(\frac{1}{2}\right)$ |
A heavy particle is projected from a point on the horizontal at an angle $60^o$ with the horizontal with a speed of $10\ m/s$ . Then the radius of the curvature of its path at the instant of crossing the same horizontal will be ......... $m$
A heavy particle is projected from a point on the horizontal at an angle $60^o$ with the horizontal with a speed of $10\ m/s$ . Then the radius of the curvature of its path at the instant of crossing the same horizontal will be ......... $m$
From the top of a tower of height $40\,m$, a ball is projected upwards with a speed of $20\,m / s$ at an angle of elevation of $30^{\circ}$. The ratio of the total time taken by the ball to hit the ground to its time of flight (time taken to come back to the same elevation) is (take $g=10\,m / s ^2$ )
From the top of a tower of height $40\,m$, a ball is projected upwards with a speed of $20\,m / s$ at an angle of elevation of $30^{\circ}$. The ratio of the total time taken by the ball to hit the ground to its time of flight (time taken to come back to the same elevation) is (take $g=10\,m / s ^2$ )