For an electron microscope,which of the follo | vedclass

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(B) The resolving power $(RP)$ of a microscope is given by $RP \propto \frac{1}{\lambda}$,where $\lambda$ is the wavelength of the particle used.For a

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Its resolving power is directly proportional to accelerating potential of electrons

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(B) The resolving power $(RP)$ of a microscope is given by $RP \propto \frac{1}{\lambda}$,where $\lambda$ is the wavelength of the particle used.For an electron,the de-Broglie wavelength is $\lambda = \frac{h}{\sqrt{2meV}}$,where $V$ is the accelerating potential.Thus,$RP \propto \frac{1}{\lambda} \propto \sqrt{V}$.Therefore,the resolving power is directly proportional to the square root of the accelerating potential,not the potential itself.Option $(b)$ is false.

For an electron microscope,which of the following is false?

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