For a thermocouple,the temperature of inversion is that temperature at which the thermo $e.m.f.$ is:

The $emf$ of a thermocouple, with one junction kept at $0^{\circ}C$, is given by the equation $e = at + bt^2$. The Peltier coefficient is given by:

If for a thermocouple ${T_n}$ is the neutral temperature,${T_c}$ is the temperature of the cold junction,and ${T_i}$ is the temperature of inversion,then:

The potential difference across $8\,\Omega$ resistance is $48\,V$ as shown in the figure. The value of potential difference across $X$ and $Y$ points will be ............. $V$.

The Thomson coefficient of a conductor is $10\,\mu V/K$. The two ends of the conductor are maintained at $50\,^{\circ}C$ and $60\,^{\circ}C$ respectively. The amount of heat absorbed by the conductor when a charge of $10\,C$ flows through it is:

As the temperature of the hot junction of a thermocouple is increased (while the cold junction is at a constant temperature), the thermo $e.m.f.$