For a series $LCR$ circuit,the power loss at resonance is

  • A
    $\frac{V^{2}}{\left[\omega L-\frac{1}{\omega C}\right]}$
  • B
    $I^{2} L \omega$
  • C
    $I^{2} R$
  • D
    $\frac{V^{2}}{C \omega}$

Explore More

Similar Questions

If the inductance and capacitance are both doubled in an $L-C-R$ circuit,the resonant frequency of the circuit will

In a series $LCR$ circuit,a resistor of $300 \ \Omega$,a capacitor of $25 \ \text{nF}$ and an inductor of $100 \ \text{mH}$ are used. For maximum current in the circuit,the angular frequency of the ac source is $. . . . \times 10^4 \ \text{rad s}^{-1}$.

An $AC$ circuit contains a resistance of $1 \text{ k}Omega$,a capacitor of $0.1 \mu\text{F}$,and an inductor of $1 \text{ mH}$ connected in series. The resonance frequency of the circuit is approximately: (in $kHz$)

What is the sharpness of resonance and obtain an equation for the $Q$ factor?

The power factor in an $L-C-R$ circuit at resonance is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo