For a reaction A longrightarrow P,a plot betw | vedclass

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(B) For a reaction of order $n$,the half-life is given by $t_{1/2} \propto \frac{1}{[A]_0^{n-1}}$.Given that the plot of $[A]_0$ $Vs$ $\frac{1}{t_{1/2

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$10$

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(B) For a reaction of order $n$,the half-life is given by $t_{1/2} \propto \frac{1}{[A]_0^{n-1}}$.Given that the plot of $[A]_0$ $Vs$ $\frac{1}{t_{1/2}}$ is a straight line with a positive slope,we have $\frac{1}{t_{1/2}} = k[A]_0$,which implies $t_{1/2} \propto \frac{1}{[A]_0}$.This corresponds to a reaction of order $n = 2$.Since $t_{1/2} 	imes [A]_0 = 	ext{constant}$,we can write: $(t_{1/2})_1 	imes [A]_1 = (t_{1/2})_2 	imes [A]_2$.Substituting the given values: $20 \ min 	imes 1 	imes 10^{-2} \ M = (t_{1/2})_2 	imes 2 	imes 10^{-2} \ M$.Solving for $(t_{1/2})_2$,we get $(t_{1/2})_2 = \frac{20 	imes 1 	imes 10^{-2}}{2 	imes 10^{-2}} \ min = 10 \ min$.

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