For a ray of light,the critical angle is mini | vedclass

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(D) The critical angle $c$ is given by the formula $\sin c = \frac{1}{\mu}$,where $\mu$ is the refractive index of the denser medium with respect to t

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glass to air.

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(D) The critical angle $c$ is given by the formula $\sin c = \frac{1}{\mu}$,where $\mu$ is the refractive index of the denser medium with respect to the rarer medium.For the critical angle to be minimum,$\sin c$ must be minimum,which implies $\mu$ must be maximum.Refractive indices are: $a\mu_w = 1.33$,$a\mu_g = 1.50$.For light traveling from glass to air,$\mu = \frac{a\mu_g}{a\mu_a} = \frac{1.5}{1} = 1.5$.For light traveling from water to glass,$\mu = \frac{a\mu_g}{a\mu_w} = \frac{1.5}{1.33} \approx 1.125$.For light traveling from glass to water,$\mu = \frac{a\mu_w}{a\mu_g} = \frac{1.33}{1.5} Comparing the values of $\mu$ for which total internal reflection is possible,the value $\mu = 1.5$ (glass to air) is the maximum.Therefore,the critical angle is minimum for light traveling from glass to air.

For a ray of light,the critical angle is minimum when it travels from

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