For a given material, the Young's modulus is | vedclass

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Question

(D) The relationship between Young's modulus $(Y)$, modulus of rigidity $(\eta)$, and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 2\eta(1

Vedclass · Accepted Answer

$0.2$

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(D) The relationship between Young's modulus $(Y)$, modulus of rigidity $(\eta)$, and Poisson's ratio $(\sigma)$ is given by the formula: $Y = 2\eta(1 + \sigma)$.Given that the Young's modulus is $2.4$ times the modulus of rigidity, we have: $Y = 2.4\eta$.Substituting this into the formula:$2.4\eta = 2\eta(1 + \sigma)$Dividing both sides by $2\eta$:$1.2 = 1 + \sigma$Solving for $\sigma$:$\sigma = 1.2 - 1 = 0.2$.Thus, the Poisson's ratio is $0.2$.

For a given material, the Young's modulus is $2.4$ times that of the modulus of rigidity. Its Poisson's ratio is

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