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(B) The power gain of an amplifier is given by the product of voltage gain and current gain.$	ext{Power Gain} = 	ext{Voltage Gain} 	imes 	ext{Curr

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$400$

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(B) The power gain of an amplifier is given by the product of voltage gain and current gain.$	ext{Power Gain} = 	ext{Voltage Gain} 	imes 	ext{Current Gain}$Given:Voltage Gain $(A_v)$ = $40$Input Impedance $(Z_i)$ = $100 \ \Omega$Output Impedance $(Z_o)$ = $400 \ \Omega$First, we calculate the current gain $(\beta)$:$	ext{Current Gain} = \frac{	ext{Output Current}}{	ext{Input Current}} = \frac{V_o / Z_o}{V_i / Z_i} = \left( \frac{V_o}{V_i} ight) 	imes \left( \frac{Z_i}{Z_o} ight)$$	ext{Current Gain} = A_v 	imes \left( \frac{Z_i}{Z_o} ight) = 40 	imes \left( \frac{100}{400} ight) = 40 	imes 0.25 = 10$Now, calculate the power gain:$	ext{Power Gain} = 40 	imes 10 = 400$

For a common-emitter amplifier, the voltage gain is $40$. Its input and output impedances are $100 \ \Omega$ and $400 \ \Omega$, respectively. The power gain of the $CE$ amplifier will be

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