For a body moving in a circular path,what is | vedclass

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(A) For a body of mass $m$ moving in a horizontal circular path of radius $r$ with speed $v$,the centripetal force required is $F_c = \frac{mv^2}{r}$.

Vedclass · Accepted Answer

$\frac{mv^2}{r} \leq \mu mg$

Vedclass · Answer

(A) For a body of mass $m$ moving in a horizontal circular path of radius $r$ with speed $v$,the centripetal force required is $F_c = \frac{mv^2}{r}$.This centripetal force is provided by the static friction force $f_s$ acting between the body and the surface.The maximum value of static friction is $f_{s,max} = \mu N = \mu mg$.For the body to move in a circular path without skidding,the required centripetal force must be less than or equal to the maximum available static friction.Therefore,the condition for no skidding is $\frac{mv^2}{r} \leq \mu mg$.

For a body moving in a circular path,what is the condition for no skidding if $\mu$ is the coefficient of friction?

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